Bug 281 : Parsing error when using char literals
Last modified: 2010-03-15 14:46




Status:
RESOLVED
Resolution:
FIXED -
Priority:
P2
Severity:
normal

 

Reporter:
Sam
Assigned To:
fry

Attachment Type Created Size Actions

Description:   Opened: 2006-01-31 19:08
The following lines of code creates an error in the Processing parser, but
shouldn't

if ( someString.charAt( n ) == '(' )
{
some code
}

The parser sees this as:

if ( someString.charAt( n ) == ( )
{
some code
}

And therefore throws an error on the first curly bracket.

It can be worked around by using the numeric values 0x28 for ( and 0x29 for )

eg: if ( someString.charAt( n ) == 0x28 )
Additional Comment #1 From fry 2006-02-01 13:25
k, changing the spacing on the parens around it may avoid the issue until it gets fixed.
Additional Comment #2 From MrFeinberg 2010-03-15 14:12
cannot reproduce; please close
Additional Comment #3 From fry 2010-03-15 14:46
can't reproduce either, may have been fixed in an earlier release. closing.